Numerical Problems/ISC/Class 11
Created by Titas Mallick
Biology Teacher • M.Sc. Botany • B.Ed. • CTET (CBSE) • CISCE Examiner
Created by Titas Mallick
Biology Teacher • M.Sc. Botany • B.Ed. • CTET (CBSE) • CISCE Examiner
Numerical Problems - Transport in Plant
A plant cell has a solute potential (Ψs) of -0.7 MPa and a pressure potential (Ψp) of 0.3 MPa. Calculate the water potential (Ψ) of this cell.
Solution:
Water potential (Ψ) is the sum of solute potential (Ψs) and pressure potential (Ψp).
Ψ = Ψs + Ψp
Given:
Ψ = -0.7 MPa + 0.3 MPa Ψ = -0.4 MPa
Therefore, the water potential of this cell is -0.4 MPa.
Cell A has a water potential of -0.5 MPa, and Cell B has a water potential of -0.8 MPa. In which direction will there be a net movement of water between these two cells?
Solution:
Water always moves from a region of higher water potential to a region of lower water potential.
Comparing the two values, -0.5 MPa is higher (less negative) than -0.8 MPa.
Therefore, there will be a net movement of water from Cell A to Cell B.
/Numerical-Problems/ISC/Class-11/Class_XI_Biology_Chapter_Transport_in_Plants_Topic_Water_Potential_Numerical_Problems.mdx