Numerical Problems/ISC/Class 11
Created by Titas Mallick
Biology Teacher • M.Sc. Botany • B.Ed. • CTET (CBSE) • CISCE Examiner
Created by Titas Mallick
Biology Teacher • M.Sc. Botany • B.Ed. • CTET (CBSE) • CISCE Examiner
Numerical Problems - Biomolecules
An enzyme catalyzes a reaction that produces 200 micromoles of product in 5 minutes. Calculate the rate of reaction in micromoles per minute.
Solution:
Rate of Reaction = (Amount of Product Formed) / Time Taken
Given:
Rate of Reaction = 200 micromoles / 5 minutes Rate of Reaction = 40 micromoles/minute
Therefore, the rate of the enzyme-catalyzed reaction is 40 micromoles per minute.
The rate of an enzyme-catalyzed reaction doubles for every 10°C rise in temperature within a certain range (Q10 = 2). If a reaction proceeds at a rate of 5 units at 20°C, what would be its approximate rate at 40°C?
Solution:
Alternatively, using the Q10 formula: Rate_T2 = Rate_T1 * (Q10)^((T2-T1)/10)
Given:
Rate_40°C = 5 * (2)^((40-20)/10) Rate_40°C = 5 * (2)^(20/10) Rate_40°C = 5 * (2)^2 Rate_40°C = 5 * 4 Rate_40°C = 20 units
Therefore, the approximate rate of the reaction at 40°C would be 20 units.
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